Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8227807
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T16:15:08+00:00 2026-06-07T16:15:08+00:00

#1 This is not working: $(‘.someclass’).fancybox({ type: ‘ajax’, href: ‘name_of_partial1’, }) #2 This is

  • 0

#1 This is not working:

$('.someclass').fancybox({
  type: 'ajax',
  href: 'name_of_partial1',
})

#2 This is working:

$('#some_id').fancybox({
  type: 'ajax',
  href: 'name_of_partial2',
})

Partial 1 and Partial 2 are in the same directory. #some_id and .some_class are elements on two different actions in the same controller.

All I want to do is render a partial inside of fancybox, is using the fancybox href option the proper way to call a partial inside of the fancybox?

The error I’m getting with the second one is the fancybox pops up with “The requested content cannot be loaded. Please try again later” and I get a 404 in the console.

When I change the href in #2 to:

href: 'name_of_partial1'

Then I see partial 1 get rendered in the fancybox.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-07T16:15:10+00:00Added an answer on June 7, 2026 at 4:15 pm

    To self:

    Turns out that the href: ” option maps to the controller action. I was getting a 404 because name_of_partial2 had a controller action that by the same name, but there was some no-good render happening in that action that was throwing a 404

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Why is this not working? <div class=videocontainer id='mediaspace-55'></div> <script type='text/javascript' src='http://ajax.googleapis.com/ajax/libs/swfobject/2.2/swfobject.js?ver=3.0.1'></script> <script type='text/javascript'><!-- var
Why is this not working? $(document).ready(function(){ var content = '<a href=http://example.com/index.php><b>Some text!</b></a> - <a
I don't know why this working: $('.deleteQuestion').live('click', function(){ $.ajax({ type: 'GET', url: '/delete_question/' +
Why is this not working $(this).parents(tr).find(td:eq(2)).html() I cant seam to get the text getthis
So why is this not working? I'm creating a regex that will match a
I want to know i can do something similar to this (not working) code
This is not working. Firebug is not throwing any error though. HTML: <table> <tr><td>BookA</td><td><a
This is not working and it is driving me nuts. I have in the
On whatever reason this is not working (says 'file not found'), set in=c:\myprogram\_save cd
Why is this thing not working? [Database(Name=Relationships_Test)] [Table(Name = Order)] public class Order {

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.