Question

a = 218500000000

s = 6
f = 2
k = 49
d = k + f + s

r = a
i = 0

while (r >= d):
  r = r - d
  #print ('r = ',r)
  i = i+1
  #print ('i = ',i)

print (i)

I think it does what I expect it to, but its way too slow to calculate such a large number, I waited 5 mins for i to print (while python used 100% cpu to calculate..), but it didn’t. Is there a more efficient way of rewriting this piece of code so I can see how many iterations (i) it takes to complete?

Many thanks

Answer 1

r = (a % d)
i = (a / d)

Use the modulo and division operators.

There is also a divmod function to calculate both together:

i, r = divmod(a,d)