Question

After adding a user profile (called user info here) my models.py file wont syncdb. I get:TypeError: __init__() takes at least 2 arguments (1 given) and all the errors above that mention the models.py file or some file relating to it.

Models.py file:

def create_user_info(sender, instance, created, **kwargs):
    if created:
        UserInfo.objects.create(user=instance)

post_save.connect(create_user_info, sender=User)

class Book(models.Model):
    title = models.CharField(max_length=50)
    author = models.CharField(max_length=50)
    def __unicode__(self):
        return self.title

class UserInfo(models.Model):
    user = models.OneToOneField(User)
    pen_name = models.CharField(max_length=30)
    activated = models.BooleanField()
    def __unicode__(self):
        return self.email + '-' + self.pen_name

Auth thing in settings.py:

AUTH_PROFILE_MODULE = 'Knights.UserInfo'

Traceback:

Traceback (most recent call last):
  File "manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/management/__init__.py", line 443, in execute_from_command_line
    utility.execute()
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/management/__init__.py", line 382, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/management/base.py", line 196, in run_from_argv
    self.execute(*args, **options.__dict__)
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/management/base.py", line 231, in execute
    self.validate()
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/management/base.py", line 266, in validate
    num_errors = get_validation_errors(s, app)
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/management/validation.py", line 30, in get_validation_errors
    for (app_name, error) in get_app_errors().items():
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/db/models/loading.py", line 158, in get_app_errors
    self._populate()
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/db/models/loading.py", line 64, in _populate
    self.load_app(app_name, True)
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/db/models/loading.py", line 88, in load_app
    models = import_module('.models', app_name)
  File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/utils/importlib.py", line 35, in import_module
    __import__(name)
  File "/Users/Mike/Desktop/Main/Django-Development/BBN/Knights/models.py", line 53, in <module>
    class Alert(models.Model):
  File "/Users/Mike/Desktop/Main/Django-Development/BBN/Knights/models.py", line 55, in Alert
    for_user = models.ForeignKey()

Answer 1

Your error does not lie in your posted code. You’ve followed the docs to the letter, so I would’ve been surprised if it did.

Instead, the error is found in your Alert class (models.py:55). for_user = models.ForeignKey() has to be for_user = models.ForeignKey(User) or for_user = models.ForeignKey(UserInfo), depending on which you prefer.

Your faulty code was trying to instantiate an instance of the class ForeignKey, which calls it’s __init__() method. That method will have a declaration of something like

def __init__(self, other_model):

and thus the error message saying that you’re missing one parameter. self gets passed implicitly, read up on the Python classes docs if you’re interested.