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Home/ Questions/Q 6009725
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T02:00:46+00:00 2026-05-23T02:00:46+00:00

After looking after several existing posts, I am still not able to get my

  • 0

After looking after several existing posts, I am still not able to get my SimpleDateFormat parser working. Here is the code:

SimpleDateFormat df = new SimpleDateFormat(
    "EEE, dd MMM yyyy HH:mm:ss Z", Locale.US);
try {
    volcanoListDate = df.parse(currentValue);
} catch (ParseException e) {
    Log.d("DEBUG", e.toString());
    Log.d("DEBUG", currentValue);
}

I always end up with a ParseException. Here is the output of the debug messages:

06-09 23:52:17.478: DEBUG/DEBUG(2436): java.text.ParseException: Unparseable date:
06-09 23:52:17.478: DEBUG/DEBUG(2436): Wed, 08 Jun 2011 03:23:55 -0500

Locale ist set and the pattern looks okay. Where am I wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-23T02:00:47+00:00Added an answer on May 23, 2026 at 2:00 am

    Here is the solution:

                SimpleDateFormat df = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss Z", Locale.US);
            try {
                volcanoListDate = df.parse(currentValue.replaceAll("\\p{Cntrl}", ""));
            } catch (ParseException e) {
                Log.d("VOLCANO_DEBUG", e.toString());
                Log.d("VOLCANO_DEBUG", currentValue);
            }
    

    The important change is .replaceAll(“\\p{Cntrl}”, “”) which removes control characters from the parsed string.
    The strange thing is, that I do not see any of those characters with Notepad++ in the xml where the string is from. However, obviously there is something and it is working now.

    Thanks for all the help!

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