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Home/ Questions/Q 8283433
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T10:43:50+00:00 2026-06-08T10:43:50+00:00

$(a[rel=example_1],a[rel=example_2],a[rel=example_3],a[rel=example_4],a[rel=example_5],a[rel=example_6],a[rel=example_7],a[rel=example_8],a[rel=example_9],a[rel=example_10]).fancybox({………… Hello, right now I have to manually enter those codes. Is there an

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$("a[rel=example_1],a[rel=example_2],a[rel=example_3],a[rel=example_4],a[rel=example_5],a[rel=example_6],a[rel=example_7],a[rel=example_8],a[rel=example_9],a[rel=example_10]").fancybox({............

Hello, right now I have to manually enter those codes.

Is there an easy way to increment the numbers?

I know I can use something similar to a[rel=example_[1-10]]. What is the correct syntax?

many thanks

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  1. Editorial Team
    Editorial Team
    2026-06-08T10:43:53+00:00Added an answer on June 8, 2026 at 10:43 am

    One potential solution would be to use a loop.

    var element = 'a[rel=example_';
    var elements = [];
    
    for(var i = 1; i <= 10; i++){
        elements.push(element + i.toString() + ']');
    }
    
    elements = elements.join(', ');
    
    $(elements).fancybox()
    

    Alternatively, if you wanted to match all elements with a rel containing “example_”, you can use an attribute selector like this:

    $('a[rel*="example_"]').fancybox()
    

    Finally, you could simply use a class to link all of the elements and select them by referencing the common class.

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