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Home/ Questions/Q 639009
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:47:40+00:00 2026-05-13T20:47:40+00:00

Assume two Java String objects: String str = <my string>; String strLower = str.toLowerCase();

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Assume two Java String objects:

String str = "<my string>";
String strLower = str.toLowerCase();

Is it then true that for every value of <my string> the expression

str.length() == strLower.length()

evaluates to true?

So, does String.toLowerCase() preserve original string length for any value of String?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:47:41+00:00Added an answer on May 13, 2026 at 8:47 pm

    Surprisingly it does not!!

    From Java docs of toLowerCase

    Converts all of the characters in this String to lower case using the rules of the given Locale. Case mapping is based on the Unicode Standard version specified by the Character class. Since case mappings are not always 1:1 char mappings, the resulting String may be a different length than the original String.

    Example:

    package com.stackoverflow.q2357315;
    
    import java.util.Locale;
    
    public class Test {
        public static void main(String[] args) throws Exception {
            Locale.setDefault(new Locale("lt"));
            String s = "\u00cc";
            System.out.println(s + " (" + s.length() + ")"); // Ì (1)
            s = s.toLowerCase();
            System.out.println(s + " (" + s.length() + ")"); // i̇̀ (3)
        }
    }
    
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