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Home/ Questions/Q 5935559
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:16:19+00:00 2026-05-22T15:16:19+00:00

Before I plan to apply some algorithm, wanted to clarify, whether easier solution is

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Before I plan to apply some algorithm, wanted to clarify, whether easier solution is available in java for this particular problem.

String str = “This is a test string”;

For the above string,

Have to insert at pos 3 – “—“
Have to insert at pos 6 – “~~~~”

How to achieve this?
Using stringBuffer , I can use API , insert(pos,char[]);

In first loop , if I insert at pos 3, second pos (pos – 6) is no longer true, To get correct pos second time , have to add no of characters previously added. (i.e. 6+3 =9).

One way is to keep track of characters that I have added. (cumbersome)
But, Is there a way where I can keep on inserting to the original text at specified position, and then make a Union of it or like that ! (basically a better approach) ?

e.g. “This is a test string”
1st loop- Thi—s is a test string
2nd loop- This i~~~~s a test string

finally o/p required is Thi—s i~~~~s a test string.

This is a part of bigger problem , before I approach that , wanted to clarify this.

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:16:19+00:00Added an answer on May 22, 2026 at 3:16 pm

    I’m not sure this is what you’re looking for, but you can start from the end, this way the indexes will still be true:

    e.g. "This is a test string"
    1st loop- This i~~~~s a test string
                    ^index 6
    2nd loop- Thi---s i~~~s a test string
                 ^index 3
    

    I find it convenient when modifying arrays as well…

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