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Home/ Questions/Q 8249471
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T23:33:21+00:00 2026-06-07T23:33:21+00:00

Below is a piece of code from Python which has been bothering me for

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Below is a piece of code from Python which has been bothering me for a while.

var=0
while (var <1 or var>100):
    var=raw_input('Enter the block number ')
    if (var >=1 and var<=100):
        print '\nBlock Number : ',var 
    else:
        print 'ERROR!!! Enter again.'

The problem is that the while loop iterates continuously without breaking. Can anyone help me how to break the loop.

Is there any way to implement a do..while in Python?

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  1. Editorial Team
    Editorial Team
    2026-06-07T23:33:22+00:00Added an answer on June 7, 2026 at 11:33 pm

    The problem is that raw_input returns a string. You’re comparing a string with an integer which you can do in python 2.x (In python 3, this sort of comparison raises a TypeError), but the result is apparently always False. To make this work you probably want something like var=int(raw_input('Enter the block number'))

    From the documentation:

    objects of different types always compare unequal, and are ordered consistently but arbitrarily.

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