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Home/ Questions/Q 6007995
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:45:42+00:00 2026-05-23T01:45:42+00:00

Calling multiMax() at the bottom of the code block we pass in 4 arguments.

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Calling multiMax() at the bottom of the code block we pass in 4 arguments. I see how the rest of the logic plays out I just don’t get why alert(multi) is equal to ‘3’;

http://jsfiddle.net/captainill/AjEPV/

function multiMax(multi){
  alert(multi);
  // Make an array of all but the first argument 
  var allButFirst = Array().slice.call( arguments, 1 ); 

  // Find the largest number in that array of arguments 
  var largestAllButFirst = Math.max.apply( Math, allButFirst );

  // Return the multiplied result 
  return multi * largestAllButFirst; 
} 
alert( multiMax(3, 1, 2, 3) == 9, "3*3=9 (First arg, by largest.)" );

I’ve been going through these excellent little tutorials:
http://ejohn.org/apps/learn/#47

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:45:42+00:00Added an answer on May 23, 2026 at 1:45 am

    alert(multi) displays “3” because multi is the first argument, and 3 is the first value you’re passing to the function.

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