Question

Can I pass number greater than 999 999 999 as parameter in java.

When I do like this it gives compiler error the literal 999 999 999 9 of type is out of range

 passNumber(9999999999);

 public String passNumber(long number){
     if(number > 999999999)
         throw new BigNumberException("Number too large")
 }

Answer 1

It’s because 9,999,999,999 is considered as an int by the compiler and is larger than Integer.MAX_VALUE (2,147,483,647).

You can use a long: 9999999999L.