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Home/ Questions/Q 8301971
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T17:10:18+00:00 2026-06-08T17:10:18+00:00

Cause I’ve tried doing the truth table unfortunately one has 3 literals and the

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Cause I’ve tried doing the truth table unfortunately one has 3 literals and the other has 4 so i got confused.

F = (A+B+C)(A+B+D')+B'C;

and this is the simplified version

F = A + B + C

http://www.belley.org/etc141/Boolean%20Sinplification%20Exercises/Boolean%20Simplification%20Exercise%20Questions.pdf

cause I think there’s something wrong with this reviewer.. or is it accurate?
btw is simplification different from minimizing from Sum of Minterms to Sum of Products?

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  1. Editorial Team
    Editorial Team
    2026-06-08T17:10:19+00:00Added an answer on June 8, 2026 at 5:10 pm

    Yes, it is the same.

    Draw the truth table for both expressions, assuming that there are four input variables in both. The value of D will not play into the second truth table: values in cells with D=1 will match values in cells with D=0. In other words, you can think of the second expression as

    F = A +B + C + (0)(D)
    

    You will see that both tables match: the (A+B+C)(A+B+D') subexpression has zeros in ABCD= {0000, 0001, 0011}; (A+B+C) has zeros only at {0000, 0001}. Adding B'C patches zero at 0011 in the first subexpressions, so the results are equivalent.

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