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Editorial Team
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Asked: 2026-05-15T10:24:36+00:00

char a[3]; int x=9; int y=8; a[0]=(char)x; a[1]=(char)y; a[2]=’\0′; unsigned char * temp=(unsigned char*)a;

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char a[3];

int x=9;
int y=8;

a[0]=(char)x;
a[1]=(char)y;
a[2]='\0';

unsigned char * temp=(unsigned char*)a;

but when i am displaying this temp, it’s displaying ?8. should display 98.

can anyone please help???

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1 Answer

  1. Editorial Team
    char a[3];

int x='9';
int y='8';

a[0]=(char)x;
a[1]=(char)y;
a[2]='\0';

unsigned char * temp=(unsigned char*)a;
printf("%s", temp);

    You were giving a value of 9 and 8, instead of their ASCII values.

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