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Home/ Questions/Q 6021619
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T03:44:22+00:00 2026-05-23T03:44:22+00:00

class Base { protected: string m_strName; char* pchChar; public: Base() { m_strName = Base;

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class Base {

    protected:
            string m_strName;
            char* pchChar;
    public:
            Base()
            {
                    m_strName = "Base";
                    pchChar   = NULL;
            };

           void display()
            {
                    printf(" display name : %s %c\n",m_strName.c_str(),pchChar);
             };
  };

 class Derived : protected Base {
       public:
               Derived()
               {
                       init();
               };

            void init()
            {
                    m_strName = "Derived";
                    pchChar = (char*)malloc(sizeof(char));
                    strcpy(pchChar,"A");
                    printf(" char %c\n",*pchChar);
                    display();
            };
};

int main()
{
        Derived* pDerived = new Derived();
        return 0;
}

The observed output is

    char A
    display name : Derived P

whereas i expected pchChar should have value “A” on both occasions.
am i missing any piece of information??
pls suggest.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T03:44:23+00:00Added an answer on May 23, 2026 at 3:44 am

    You forgot *:

    printf(" display name : %s %c\n",m_strName.c_str(), *pchChar);
    

    It should be *pchChar, not pchChar. Because you’re printing it as %c.

    Or you can use %s as format string, and your printf would work, if the c-string is null-terminated string. Currently its not null-terminated. You should be doing this:

    pchChar = (char*)malloc( 2 * sizeof(char)); //2 chars, one for `\0`
    strcpy(pchChar,"A");
    

    Or even better use new, and std::cout.

    Also, don’t forget to call free with malloc to deallocate the memory once you’re done with it. And if you use new, use delete.

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