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Home/ Questions/Q 8336035
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:51:46+00:00 2026-06-09T03:51:46+00:00

Code Design 1 : works perfectly public static void main (String[] args) { recursion(2);

  • 0

Code Design 1 : works perfectly

 public static void main (String[] args)
    {       
        recursion(2);       
    }

    public static void recursion(int num)
    {
        if (num > 0)
        {
            recursion( num - 1 );
            System.out.println(num);
        }   
    }

Code Design 2 : Infinite Loop. ?

public static void main (String[] args)
    {       
        recursion(2);       
    }

    public static void recursion(int num)
    {
        if (num == 0) return;
        while (num > 0)
        {
            recursion( num - 1 );
            System.out.println(num);
        }   
    }
  1. Can someone plz help me in understanding why 2nd design is getting
    into infinite loop?
  2. I have already put return in 2nd design . So it should have worked
    fine. Also can you plz give me explanation in detail?
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  1. Editorial Team
    Editorial Team
    2026-06-09T03:51:48+00:00Added an answer on June 9, 2026 at 3:51 am

    1. First of all if is Not a Loop, we only have for loop, for-each, while loop and do-while loop.

    2. The reason for the 2nd code to go in for a Infinite loop is that, you are never decrementing the value of num.

    Do this….

    while (num > 0)
        {
            recursion( num - 1 );
            System.out.println(num);
            num = num - 1;           // Decrementing the value of num by 1
        }  
    
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