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Home/ Questions/Q 872691
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:49:19+00:00 2026-05-15T10:49:19+00:00

Code: for($i = 1; $i <= $arr[‘var’]; $i++) { if($i == $arr[‘var’]): $insert .=

  • 0

Code:

for($i = 1; $i <= $arr['var']; $i++) {

  if($i == $arr['var']):

    $insert .= '('.$n_id.', 12)';

  else:

    $insert .= '('.$n_id.', 12),';

  endif;

}

$uz = mysql_query("INSERT INTO `cars`
                   (n_id, auto_id)
                   VALUES
                   '$insert'") or die(mysql_error());

Why it gives me a SQL syntax error? What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:49:20+00:00Added an answer on May 15, 2026 at 10:49 am

    You’re missing string concatentation in the INSERT statement:

    $uz = mysql_query("INSERT INTO `cars`
                         (n_id, auto_id)
                       VALUES "
                        . $insert .") or die(mysql_error());
    

    That’s assuming you aren’t also having an issue with the trailing comma for tuple support.

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