Question

Code Used(db connection already established):

<?php 
$cur = mysql_query("SELECT MAX(id) FROM trades");
echo "$cur";
while($cur >= 0) {
$query = mysql_query("SELECT * FROM trades WHERE id='$cur'");

if(mysql_num_rows($query)==0) {
    echo "ERROR!";
    exit();
}
$row = mysql_fetch_assoc($query);

$tradeID = $row['ID'];
$mcUsername = $row['Minecraft Username'];
$blockID = $row['Block ID'];
$quantity = $row['Quantity'];
$costPer = $row['CostPer'];
$tradeNotes = $row['TradeNotes'];

    echo "<tr>";
    echo "<td class='first-td'>$tradeID</td>";
    echo "<td>$mcUsername</td>";
    echo "<td>$blockID</td>";
    echo "<td>$quantity</td>";
    echo "<td>$costPer</td>";
    echo "<td class='last-td'>$tradeNotes</td>";
    echo "</tr>";

    $cur = "$cur - 1";
} 
?>

The echo of the $cur is returning : Resource id #7

And the if statement is returning ERROR, which is most likely caused due to $cur not working right.

Is there some kind of syntax error in what I’m doing because when I run the SQL query for $cur manually in MySQL DB it returns the expected value.

Answer 1

Try this

$res = mysql_query("SELECT MAX(id) FROM trades");
$row = mysql_fetch_row($res);
$cur = $row[0];
echo "$cur";

mysql_query returns a resource for select query not a value. Check what is returned by mysql_query and notice the warning against using mysql_ function