Question

CODE1:

while( $row1 = mysql_fetch_array($result2) && $row2 = mysql_fetch_array($result4) )
{
 $details[0] = $row1[0];
 $details[1] = $row2[0];
 var_dump($details[0]);
 var_dump($details[1]);
}

OUTPUT1:

NULL string(1) "5" 

CODE2:

while($row1 = mysql_fetch_array($result2))
{
 $details[0] = $row1[0];
 var_dump($details[0]);
}
while($row2 = mysql_fetch_array($result4))
{
 $details[1] = $row2[0];
 var_dump($details[1]);
}

OUTPUT2:

string(6) "728548" string(1) "5"

**OUTPUT2** is the desired result. I have checked the rest portion of my code that I haven’t mentioned here, nothing is wrong with that. Using **CODE1** instead of **CODE2** gives wrong result. I tried **CODE1** just for reducing the length of my code but it isn’t working. Why can’t we use more than one mysql_fetch_array() like I did in **CODE1** ?

Answer 1

The operator precedence of && is higher than =. So, put parenthesis around the two parts and try this:

while(($row1 = mysql_fetch_array($result2)) && ($row2 = mysql_fetch_array($result4)))