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Home/ Questions/Q 8247813
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T22:58:45+00:00 2026-06-07T22:58:45+00:00

Coffeescript code: class Animal constructor: (@name) -> move: (meters) -> alert @name + moved

  • 0

Coffeescript code:

class Animal
  constructor: (@name) ->

  move: (meters) ->
    alert @name + " moved #{meters}m."

class Snake extends Animal
  move: ->
    alert "Slithering..."
    super 5

alert Snake instanceof Animal

Here is a link.

I really think this result true.
And my reason is this __extends method in compiled JavaScript:

__extends = function (child, parent) {
    for(var key in parent) {
        if(__hasProp.call(parent, key)) child[key] = parent[key];
    }function ctor() {
        this.constructor = child;
    }
    ctor.prototype = parent.prototype;
    child.prototype = new ctor();
    child.__super__ = parent.prototype;
    return child;
};

child.prototype.prototype is parent.

Can someone tell me why?
And I know below is true:

alert new Snake('a') instanceof Animal
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  1. Editorial Team
    Editorial Team
    2026-06-07T22:58:48+00:00Added an answer on June 7, 2026 at 10:58 pm

    Your Snake is a subclass of Animal:

    class Snake extends Animal
    

    That means that Snake (a “class”) is actually an instance of Function, not Animal. A Snake object, on the other hand, would be an instance of Animal:

    alert Snake instanceof Function     # true
    alert (new Snake) instanceof Animal # true
    

    And if you try to get a Snake instance to move:

    (new Snake('Pancakes')).move()
    

    you’ll see that the right methods are called.

    Demo: http://jsfiddle.net/ambiguous/3NmCZ/1/

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