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Home/ Questions/Q 695295
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T02:56:40+00:00 2026-05-14T02:56:40+00:00

Consider the following code: class Base { void f() { } }; class Derived:

  • 0

Consider the following code:


class Base
{
    void f() { }
};

class Derived: public Base
{
public:

};

What can you change in the derived class, such that you can perform the following:


Derived d;
d.f();

If the member is declared as public in the base class, adding a using declaration for Base::f in the derived class public section would’ve fix the problem. But if it is declared as private in the base class, this doesn’t seem to work.

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  1. Editorial Team
    Editorial Team
    2026-05-14T02:56:41+00:00Added an answer on May 14, 2026 at 2:56 am

    This is not possible. A using declaration can’t name a private base class member. Not even if there are other overloaded functions with the same name that aren’t private.

    The only way could be to make the derived class a friend:

    class Derived;
    
    class Base
    {
        void f() { }
        friend class Derived;
    };
    
    class Derived: public Base
    {
    public:
        using Base::f;
    };
    

    Since you make the names public in the derived class anyway so derived classes of Derived will be able to access them, you could make them protected in the base-class too and omit the friend declaration.

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