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Home/ Questions/Q 1002399
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:49:37+00:00 2026-05-16T07:49:37+00:00

Consider this: One mySQL database that has tables and rows and data within it.

  • 0

Consider this:

One mySQL database that has tables and rows and data within it.

One array that has the same data.

Now normally, I would have a query like this for mySQL SELECT * FROM 'table' WHERE name LIKE '%abc%'

But I want to perform that same query on the array, without having to insert it yet. The only method that comes to mind is using array_search, but the syntax is different and the method is convoluted.

Is there a shortcut here?

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:49:38+00:00Added an answer on May 16, 2026 at 7:49 am

    You can’t use SQL with arrays, but one way you could do your example is using array_filter():

    function like_abc($v) {
        return strstr($v['name'], 'abc') !== false;
    }
    
    $filtered = array_filter($yourArray, 'like_abc');
    

    or if you are using PHP >= 5.3.0

    $filtered = array_filter($yourArray, 
        function($v) { return strstr($v['name'], 'abc') !== false;});
    

    See it in action on ideone


    You can also try PHPLinq:

    // UNTESTED CODE!
    $yourArray = array (
        array('name' => 'abcd', 'age' => 20),
        array('name' => 'dacb', 'age' => 45),
        array('name' => 'aadd', 'age' => 32),
        array('name' => 'babc', 'age' => 11),
        array('name' => 'afgb', 'age' => 17),
    );
    
    $result = from('$people')->in($yourArray)
                ->where('$people["name"] => strstr($people["name"], "abc") !== false')
                ->select('$people'); 
    
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