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Home/ Questions/Q 8335411
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:40:14+00:00 2026-06-09T03:40:14+00:00

Currently I get back a JSON response like this… {items:[ {itemId:1,isRight:0}, {itemId:2,isRight:1}, {itemId:3,isRight:0} ]}

  • 0

Currently I get back a JSON response like this…

{items:[
  {itemId:1,isRight:0},
  {itemId:2,isRight:1},
  {itemId:3,isRight:0}
]}

I want to perform something like this (pseudo code)

var arrayFound = obj.items.Find({isRight:1})

This would then return

[{itemId:2,isRight:1}]

I know I can do this with a for each loop, however, I am trying to avoid this. This is currently server side on a Node.JS app.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:40:16+00:00Added an answer on June 9, 2026 at 3:40 am
    var arrayFound = obj.items.filter(function(item) {
        return item.isRight == 1;
    });
    

    Of course you could also write a function to find items by an object literal as a condition:

    Array.prototype.myFind = function(obj) {
        return this.filter(function(item) {
            for (var prop in obj)
                if (!(prop in item) || obj[prop] !== item[prop])
                     return false;
            return true;
        });
    };
    // then use:
    var arrayFound = obj.items.myFind({isRight:1});
    

    Both functions make use of the native .filter() method on Arrays.

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