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Home/ Questions/Q 8331257
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T02:21:36+00:00 2026-06-09T02:21:36+00:00

Currently, I have the following code: runtable={} for _,v in pairs(akeys) do if string.match(string.upper(v),string.upper(area))

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Currently, I have the following code:

runtable={}
for _,v in pairs(akeys) do
  if string.match(string.upper(v),string.upper(area)) then
    table.insert(runtable,area)
    break
  end
end

if #runtable = 0 then
  for i,_ in pairs(akeys) do
    if string.match(string.upper(i),string.upper(area)) then
    table.insert(runttable,area)
    end
  end
end

The purpose of this script is to go through all the values first and see if the area variable matches the value. If it does, it’s going to be a one-time thing, so it’ll stop the loop and continue on with the rest of the script (beyond the if #runtable = 0). If it fails to find anything in the values, then it goes through the list again, but this time comparing indices to the area, and each time it finds a match (partial or full), it’ll add it to the runtable.

Is there a more efficient way to do this? Or is this the best possible way to run this, regardless of how cluttered it may look?

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  1. Editorial Team
    Editorial Team
    2026-06-09T02:21:39+00:00Added an answer on June 9, 2026 at 2:21 am
    local rt1, rt2 = {}, {}
    for i,v in pairs(akeys) do
      if string.match(string.upper(v),string.upper(area)) then
        table.insert(rt1,area)
        break
      end
      if string.match(string.upper(i),string.upper(area)) then
        table.insert(rt2,area)
      end
    end
    
    local runtable = #rt1 > 0 and rt1 or rt2
    

    Not a huge saving in terms of ugliness, but it saves a second loop. Sadly there’s no kind of magic I’m aware of that’ll make this much prettier, but that’s one of the tradeoffs of having a language as compact as Lua.

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