Question

Currently im facing the problem I need to create an instance of Dictionary with any type of its cases. The types are delivered by the arguments of the method.
I do not simply want to create a dynamic or object type Dictionary, because this faces the user alot of convertion problems by using my library.
I also cannot use a simple constructor, because my method fills the Dictionary with data (that is stored in a file) in real. It’s important to create the specific dictionary by Type variables.
This is what im thinking of:

public static Dictionary<dynamic, dynamic> createDict(Type type1, Type type2)
{
    // how to create the dictionary?
    // im filling my dictionary with any data ...
    return dict;
}

Here the user calls my method:

Dictionary<string, int> dict = MyLib.createDict(typeof(string), typeof(int));
// or
MyOwnType myInstance = new MyOwnType();
Dictionary<string, MyOwnType> dict = MyLib.createDict(typeof(string), myInstance.GetType());

Answer 1

Type dictType = typeof(Dictionary<, >).MakeGenericType(Type1, Type2);
var dict = Activator.CreateInstance(dictType);

• Get the Type for Dictionary
• Create a generic type with the specified Types using MakeGenericType
• Create an instance of the generic type using Activator.CreateInstance