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Home/ Questions/Q 1044347
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:48:49+00:00 2026-05-16T15:48:49+00:00

$(document).ready(function() { $(‘a#fav’).bind(‘click’, function() { addFav(<?php echo $showUP[uID]; ?>); }); }); I need to

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$(document).ready(function() {    
    $('a#fav').bind('click', function() {
        addFav(<?php echo $showUP["uID"]; ?>);
    });
});

I need to modify this so if the a#fav has class=”active” then it should do

  removeFav(<?php echo $showUP["uID"]; ?>);

instead
How can i do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:48:50+00:00Added an answer on May 16, 2026 at 3:48 pm

    You want to use the hasClass function

    $(document).ready(function() {    
        $('a#fav').bind('click', function() {
            if($(this).hasClass('active')) {
                removeFav(<?php echo $showUP["uID"]; ?>);
            }
            else {
                addFav(<?php echo $showUP["uID"]; ?>);
            }
        });
    });
    

    EDIT: And just for fun, another way to write it in a more condensed format

    $(function() {    
        $('a#fav').bind('click', function() {
            var uID = <?php echo $showUP["uID"]; ?>;
            ($(this).hasClass('active') ? removeFav : addFav)(uID);
        });
    });
    
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