Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 515113
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T07:35:41+00:00 2026-05-13T07:35:41+00:00

Each time i vote up or down it just sets an 1. But i

  • 0

Each time i vote up or down it just sets an 1.
But i want that votes_up=votes_up+1 inkrements eachtime i vote up.

this is php code

 public function voteUp($id)
  {
    $this->initDB();

    $q="update twitter.tweets set vote_up=vote_up+1 where id=$id";
    $this->db->query($q);
  }

the result is

Down Votes:1

Up Votes:1

Total Votes:18

How can i solve that Down Votes and Up Votes are inkremented?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T07:35:41+00:00Added an answer on May 13, 2026 at 7:35 am

    You aren’t setting $id or something else is going wrong. This SQL looks fine. .

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Each time I add in the correct code, it gives me the same error
Each time my user signs in, we pull his profile picture from Facebook. This
I have one windows form file that each time I open it in Visual
I want my program to get notification each time someone makes a post to
I have a Post, Comment and Vote model Each time an instance of Vote
Each time I run a command like this ssh user@myhost.com I've to type in
I have this code: $(document).ready(function() { $(.vote, .vote1).click(function() { var id = $(this).attr(id); var
Each time I use Merge() I have the following: 'Cannot implicitly convert type 'void'
Each time my webpage is loaded it runs a routine in the page_load event
Each time I click on the map a new marker is placed on the

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.