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Home/ Questions/Q 697553
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T03:10:48+00:00 2026-05-14T03:10:48+00:00

Error % javac StringTest.java StringTest.java:4: variable errorSoon might not have been initialized errorSoon[0] =

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Error

% javac  StringTest.java 
StringTest.java:4: variable errorSoon might not have been initialized
        errorSoon[0] = "Error, why?";

Code

public class StringTest {
        public static void main(String[] args) {
                String[] errorSoon;
                errorSoon[0] = "Error, why?";
        }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T03:10:48+00:00Added an answer on May 14, 2026 at 3:10 am

    You need to initialize errorSoon, as indicated by the error message, you have only declared it.

    String[] errorSoon;                   // <--declared statement
    String[] errorSoon = new String[100]; // <--initialized statement
    

    You need to initialize the array so it can allocate the correct memory storage for the String elements before you can start setting the index.

    If you only declare the array (as you did) there is no memory allocated for the String elements, but only a reference handle to errorSoon, and will throw an error when you try to initialize a variable at any index.

    As a side note, you could also initialize the String array inside braces, { } as so,

    String[] errorSoon = {"Hello", "World"};
    

    which is equivalent to

    String[] errorSoon = new String[2];
    errorSoon[0] = "Hello";
    errorSoon[1] = "World";
    
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