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Home/ Questions/Q 873205
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:53:49+00:00 2026-05-15T10:53:49+00:00

errors = {} #errorexample errors[‘id’] += (‘error1’,) errors[‘id’] += (‘error2’,) #works but ugly errors[‘id’]

  • 0
errors = {}

#errorexample
errors['id'] += ('error1',)
errors['id'] += ('error2',)

#works but ugly
errors['id'] = ('error1',)
errors['id'] += ('error2',)

If ‘error1’ is not present it will fail. Do I really have to extend dict?

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:53:50+00:00Added an answer on May 15, 2026 at 10:53 am

    Use a collections.defaultdict instead of a plain dict — this kind of convenience, after all, is exactly what the default-dict type was introduced for:

    >>> import collections
    >>> errors = collections.defaultdict(tuple)
    >>> errors['id'] += ('error1',)
    >>> errors['id'] += ('error2',)
    >>> errors['id']
    ('error1', 'error2')
    
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