Question

FI have many code which contains code snippet like:

#if wxCHECK_VERSION(2, 9, 0)
Codef( _T("%AAppend(%t)"), ArrayChoices[i].wx_str());
#else
Codef( _T("%AAppend(%t)"), ArrayChoices[i].c_str());
#endif

But I want to clean the code to

Codef( _T("%AAppend(%t)"), ArrayChoices[i].wx_str());

I mean, I need to strip the preprocessor directive, and only leave the first branch.

The match condition should be:

#if wxCHECK_VERSION(2, 9, 0)
blablabla1
#else
blablabla2
#endif

The content of blablabla1 and blablabla2 should be the same only except the wx_str and c_str.

See here, someone said it can be handled by regex, but I have no idea, can you help me? Thanks.

EDIT:
I just want to strip the #else branch, and only keep the first branch contents.

Here is the reference page:

Re: what’s the best and quick way to remove all the wx_str and c_str preprocessor

Answer 1

Search

This regex works for your examples:

\s+#if wxCHECK_VERSION\(2\, 9\, 0\)\s*(.*?)wx_str([^\r\n]*?)\s*#else\s*(\1)c_str(\2)\s*#endif

Replacement

Regexr.com: Replace with: $1wx_str$2. Don’t forget to select dotall option.

Notepad++: Replace with: \1wx_str\2. Don’t forget to select . matches newline option.

Batch Mode

Notepad++ allows to find/replace in batch mode.

1. Open "Find in Files" dialog pressing Ctrl+Shift+H.
2. Copy-paste above regex to "Find what" box.
3. Copy-paste above replacement (\1wx_str\2) to "Replace with" box.
4. Specify Directory to find/replace in it.
5. Select Regular Expression in Search mode group box.
6. Check the . matches newline box.
7. Click to "Find All" button to view matches.
8. Click to "Replace in Files" button when you are sure to replace everything.