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Home/ Questions/Q 367235
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:42:31+00:00 2026-05-12T13:42:31+00:00

Following on from a previous question , I am having trouble combining the Lazy<T>

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Following on from a previous question, I am having trouble combining the Lazy<T> generic that was suggested with my XML Serialization.

Here is the functionality I am using for Lazy<T>:

public struct Lazy<T> where T : class, new()
{
    private T _Value;

    public bool HasValue
    {
        get
        {
            return (_Value != null);
        }
    }

    public T Value
    {
        get
        {
            if (!HasValue)
                _Value = new T();

            return _Value;
        }
    }
}

Now the MSDN Docs say that it’s fine to have an [XmlElement(“ElementName”)] on a property and it does indeed seem to be able to deserialize just fine. The problem comes when I am serializing an object. I am running the following piece of code:

class SomeClass
{
    [XmlElement("ExternalElementName")]
    public ComplexElementType InternalElementName
    { 
        get { return _InternalElementName.Value; } 
    }

    protected Lazy<ComplexElementType> _InternalElementName;
}

Elsewhere:

SomeClass someClass = new SomeClass();
someClass.InternalElementName.ComplexElementTypeChild = "some string";

// serialize...

The strange thing is, this works fine in the debugger but no element is output in the XML. Non Lazy<T> elements work fine. Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:42:31+00:00Added an answer on May 12, 2026 at 1:42 pm

    The problem is that the property has no setter. Even if it would be possible to get the value to serialise it, it can’t be deserialised as there is no way to put the value back in the new object.

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