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Home/ Questions/Q 8200969
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T06:38:18+00:00 2026-06-07T06:38:18+00:00

for example, $(document) // [ #document ] : document object in array typeof $(document)

  • 0

for example,

$(document) // [ #document ] : document object in array
typeof $(document) // "object"
$(document).constructor // function Object() { [native code] } or function (a,b) { return some function; }

If value is array, it have to be Array constructor.

It’s not an array like object. because array like object just has array property, not like [].

How can it be?

add:
If you can, show simple example code, please.
like

a = ... 
console.log(a) // [ ... ]
console.log(a.constructor) // function Object or something
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T06:38:21+00:00Added an answer on June 7, 2026 at 6:38 am

    Take a look at the jQuery source. $(document) creates a cloned jQuery object of the document element and then makes and returns an array-like object.

    the jQuery factory function $() returns a jQuery object that has many
    of the properties of an array (a length, the [] array access operator,
    etc.), but is not exactly the same as an array and lacks some of an
    array’s built-in methods (such as .pop() and .reverse()).

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