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Editorial Team
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Asked: 2026-05-24T08:51:22+00:00

For testing purposes, let’s say input.PHP looks like this <?php { $TO = joe@net.net;

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For testing purposes, let’s say input.PHP looks like this

<?php
{
$TO = "joe@net.net";
$FROM = "bob@net.net";
$SUB = "Yadda";
$BODY = "This is a test";
exec("/usr/bin/php /xxx.yyy.net/TESTS/sendit.PHP $TO $SUB $BODY $FROM > /dev/null &");
echo "DONE";
}
?>

And the sendit.PHP which is called by exec() looks like this

<?php
$to      = $argv[1];
$subject = $argv[2];
$message = $argv[3];
$headers = 'From: '.$argv[4]. "\r\n" .
'Reply-To: '.$argv[4]. "\r\n" .
'X-Mailer: PHP/' . phpversion();

mail($to, $subject, $message, $headers);
?>

When I open input.PHP in my browser, I get the echo DONE message, but the test email is not sent. What’s wrong with my code? Thank You.

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1 Answer

  1. Editorial Team

    Without error information, I’m not sure if this is the entire problem, but I’d start with this:

    Arguments as read by $argv are space-delimited. The following code:

     /usr/bin/php /xxx.yyy.net/TESTS/sendit.PHP $TO $SUB $BODY $FROM > /dev/null &

    is executing as follows in your example:

     /usr/bin/php /xxx.yyy.net/TESTS/sendit.PHP joe@net.net Yadda This is a test bob@net.net > /dev/null &

    That makes $argv[3] == 'This' and $argv[4] == 'is'.

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