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Home/ Questions/Q 8303437
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T17:32:32+00:00 2026-06-08T17:32:32+00:00

from the given html : <span class=flag_16 left_16 armenia_16_left> First League</span> how i can

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from the given html :

 <span class="flag_16 left_16 armenia_16_left"> First League</span>

how i can get the (armenia) string only or at least (armenia_16_left).

thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-08T17:32:34+00:00Added an answer on June 8, 2026 at 5:32 pm

    Use this XPath 1.0 expression:

    substring-before(substring-after(substring-after(/span /@class, ' '), ' '), '_')
    

    In XPath 2.0 one can simply use:

    tokenize(tokenize(/span /@class, ' ')[last()], '_')[1]
    

    XSLT-based verification:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output method="text"/>
    
     <xsl:template match="/">
      "<xsl:value-of select=
       "substring-before(substring-after(substring-after(/span /@class, ' '), ' '), '_')
       "/>"
     </xsl:template>
    </xsl:stylesheet>
    

    when this transformation is applied on the provided XML document:

    <span class="flag_16 left_16 armenia_16_left"> First League</span>
    

    the Xpath expression is evaluated and the result is copied to the output:

    "armenia"
    

    When this XSLT 2.0 transformation is applied on the same XML document (above):

    <xsl:stylesheet version="2.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output method="text"/>
    
     <xsl:template match="/">
      "<xsl:sequence select=
       "tokenize(tokenize(/span /@class, ' ')[last()], '_')[1]"/>"
     </xsl:template>
    </xsl:stylesheet>
    

    again the same correct result is produced:

    "armenia"
    
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