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Home/ Questions/Q 6119147
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:31:06+00:00 2026-05-23T15:31:06+00:00

Given the following code: const int size = 20; char buffer[size]; // From the

  • 0

Given the following code:

const int size = 20;
char buffer[size];

// From the Linux man page for snprintf():
//
// The 'res' is the number of bytes that would be written to buffer had size been
// sufficiently large excluding the terminating null byte.  Output bytes beyond
// the size-1st are discarded instead of being written to the buffer, and a null
// byte is written at the end of the bytes actually written into the buffer.
int res = snprintf(buffer, size, "some format with %d and %s", 23, "some string");

if (res >= size) {
  cerr << "The buffer was not large enough, we needed " << res
       << " but only had " << size << "." << endl;
} else {
  cout << "The buffer is big enough, we only needed " << res
       << " but had " << size << "." << endl;
}

Is this portable and if so, did I get all the fencepost conditions correct?

1 Passing size to snprintf()

2 Checking res being greater than or equal to size

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:31:06+00:00Added an answer on May 23, 2026 at 3:31 pm

    snprintf isn’t strictly speaking portable, as it’s not part of the C/C++ standards. Windows has it as _snprintf – but otherwise identical.

    The fencepost conditions are all fine. Your printf’s aren’t entirely fine, in the equals case it’s going to print

    The buffer was not large enough, we needed 215 but only had 215.
    
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