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Home/ Questions/Q 3220574
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T15:46:38+00:00 2026-05-17T15:46:38+00:00

Gson gson = new Gson(); Map<String,Object> map = new HashMap<String, Object>(); map.put(a, 1); map.put(b,

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Gson gson = new Gson();

Map<String,Object> map = new HashMap<String, Object>();
map.put("a", 1);
map.put("b", null);

System.out.println(gson.toJson(map)); //prints {"a":1}

How do I get it to include all entries?

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  1. Editorial Team
    Editorial Team
    2026-05-17T15:46:38+00:00Added an answer on May 17, 2026 at 3:46 pm

    See Gson User Guide – Null Object Support:

    The default behaviour that is implemented in Gson is that null object fields are ignored. This allows for a more compact output format; however, the client must define a default value for these fields as the JSON format is converted back into its Java form.

    Here’s how you would configure a Gson instance to output null:

    Gson gson = new GsonBuilder().serializeNulls().create();
    
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