Question

hello i have the code bellow:

<script type="text/javascript">
 14         $(document).ready(function() {
 15                 $('#find').click(function(){
 16                         
 17                         var amount = $('#amount').val();
 18 
 19                         $.ajax({
 20                                 type: "POST",
 21                                 contentType: "text/xml;charset=utf-8",
 22                                 url: "questions.php",
 23                                 data: {'amount': amount},
 24                                 success: function(data){
 25                                         
 26                                         $('#results').show();
 27                         
 28                                         
 29                                         $('#results').html(data);
 30                                 }
 31                         });
 32                 });
 33         });
 34     </script>

and my php script has the code below

5 $search_term = $_POST['amount'];
6 echo $search_term;

if i remove line 21 with content type thing i get the input as output but with that i get nothing as output! The thing is that i really need the content type thing so any info on that would be really helpful!

Answer 1

You’re sending the data as form data, but declaring the sent data as XML. PHP cannot parse JSON data when it’s expecting XML so doesn’t return anything. And it’s optional to set contentType.

From the jQuery Documentation:

contentType Default: ‘application/x-www-form-urlencoded; charset=UTF-8’

When sending data to the server, use this content type.
Default is “application/x-www-form-urlencoded; charset=UTF-8”, which
is fine for most cases. If you explicitly pass in a content-type to
$.ajax(), then it’ll always be sent to the server (even if no data is
sent). If no charset is specified, data will be transmitted to the
server using the server’s default charset; you must decode this
appropriately on the server side.