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Home/ Questions/Q 8372467
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T14:26:22+00:00 2026-06-09T14:26:22+00:00

Here is a snippet of my code; it is from an HTML form page:

  • 0

Here is a snippet of my code; it is from an HTML form page:

Phone Number:<input type="text" id="Phone" name="Phone" onkeyup="checkFirst();" /><br />

<p id="rabbit"></p> <!-- for testing -->

This is the input text field and I want to call upon my checkFirst function which is in the head section of the html, here is my checkFirst function

<script type="text/javasciprt">
        document.getElementById("rabbit").innerHTML = "When";
        function checkFirst(){
            var numbers = 3; //document.getElementById("Phone").value.length;
            document.getElementById("rabbit").innerHTML="Hello";
            
            if (numbers <= 3) {
                document.Phone.focus();
            } else {
                document.info_open.focus();
            }
        }
</script>

When I run this the, nothing happens to the element with the ip "rabbit". it does not change. I ran it with the Chrome debugger and it showed in the right hand panel that I have a reference error under which it says:

type: "not_defined"

The error is on the line of the element for phone input, why am I getting this error? I thought I defined type as ‘text’.

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  1. Editorial Team
    Editorial Team
    2026-06-09T14:26:23+00:00Added an answer on June 9, 2026 at 2:26 pm

    Change

    <script type="text/javasciprt">
    

    to

    <script type="text/javascript">
    

    Because the code runs perfectly in jsfiddle ( http://jsfiddle.net/yhFfc/ ).

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