Question

Here is how I set my Array:

 $Post_Cat_Array = array();
 while($row = mysql_fetch_array( $result )) {
 $Post_Cat_Array[$row['type_id']] = $row['type_name'];}

in this function I need to get the type_id(key) of a specific type_name(value)

function NameToID($input){
echo array_search($input, $Post_Cat_Array); 
}

and I call the function like this :

NameToID($_POST['type']);

But it’s not working. It doesn’t echo anything. I am sure the $_POST['type'] contains correct value.

note:value of $_POST['type'] is in arabic. same with all values of the array.

Answer 1

It seems that $Post_Cat_Array is out of scope. Modify your function:

function NameToID($input, $arr){
  echo array_search($input, $arr); 
}

and then:

NameToID($_POST['type'], $Post_Cat_Array);

From PHP Variable scope:

This script will not produce any output because the echo statement
refers to a local version of the (…) variable, and it has not been
assigned a value within this scope.