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Home/ Questions/Q 8246741
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T22:36:21+00:00 2026-06-07T22:36:21+00:00

Here is my code for my logical comparison operator (==) overloaded. I use this

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Here is my code for my logical comparison operator (==) overloaded. I use this to check if two strings are identical in size and content. It should return false otherwise.

 bool MyString::operator==(const MyString& other)const
 {
    if(other.Size == this->Size)
    {
        for(int i = 0; i < this->Size+1; i++)
        {
            if(&other == this)                          
                  return true;            
        }
    }
    else
        return false;
 }

When I ran valgrind it told me warning control reaches end of non-void function. Any suggestions on how to fix this issue and what I could do to better the code?

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  1. Editorial Team
    Editorial Team
    2026-06-07T22:36:24+00:00Added an answer on June 7, 2026 at 10:36 pm

    When control reaches the end of your for loop, you immediately get to the end of the function without returning a value.

    It looks to me like you have the logic in your for loop munged anyway — it’s comparing the address of the other item to this. While it’s sort of okay to do that, you only need to do it once, not in a loop.

    In the loop, you undoubtedly want to compare the characters in the string, not the addresses of the objects.

    Edit:

    A typical implementation would be something on this general order:

    class MyString { 
        char *data;
        size_t length;
    public:
        // ...
        bool operator==(MyString const &other) const {
            if (length != other.length)
                return false;
            for (int i=0; i<length; i++)
                if (data[i] != other.data[i]) // If we see any inequality
                    return false;             //     they're not equal
            return true;                      // all equal, so the strings are equal.
        }
    };
    
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