Question

Here is my problem. Immediately after I type in some input and hit enter the program executes. And I some how figured out that the problem was due to the for loop which I was using. Here is the code.

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

main(){


 char myString[100]; 
 char myChar = myString[6];
 int i;

 for(i=0; i<=100; i++){
    scanf("%s", myString[i]);
 }

 printf("%c\n", myChar); 
 system("pause");

}

Answer 1

You are attempting to read 101 strings %s, but you allocated space for 100 characters. You pass a character instead of a character pointer to scanf, causing a crash.

If you are trying to read 100 characters, you should pass %c in the format line, and an address in the parameter part of scanf call:

scanf("%c", &myString[i]);

You should also either replace <= with <, or allocate myString[101].

If you are looking to get one string, call scanf once, not in a loop:

scanf("%99s", myString); // myString is the same as &myString[0]

You are also reading the 6-th character before you place any data into the character array. That value is not going to change after the for loop.