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Home/ Questions/Q 4615688
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Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T01:52:33+00:00 2026-05-22T01:52:33+00:00

heres my code: $sql = mysql_query(select c.name, c.address, c.postcode, c.dob, c.mobile, c.email, count(select *

  • 0

heres my code:

$sql = mysql_query("select c.name, c.address, c.postcode, c.dob, c.mobile, c.email, 
                    count(select * from bookings where b.id_customer = c.id) as purchased, count(select * from bookings where b.the_date > $now) as remaining, 
                    from customers as c, bookings as b 
                    where b.id_customer = c.id
                    order by c.name asc");

you can see what i am trying to do, but im not sure how to write this query properly.

heres the error i get:

Warning: mysql_fetch_assoc(): supplied
argument is not a valid MySQL result
resource

heres my mysql_fetch_assoc:

<?php

while ($row = mysql_fetch_assoc($sql))
{
    ?>

    <tr>
    <td><?php echo $row['name']; ?></td>
    <td><?php echo $row['mobile']; ?></td>
    <td><?php echo $row['email']; ?></td>
    <td><?php echo $row['purchased']; ?></td>
    <td><?php echo $row['remaining']; ?></td>
    </tr>

    <?php   
}

?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T01:52:33+00:00Added an answer on May 22, 2026 at 1:52 am

    Try changing the likes of…

    count(select * from bookings where b.id_customer = c.id)
    

    …to…

    (select count(*) from bookings where b.id_customer = c.id)
    
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