Question

Here’s the code :

cout << "Please enter the file path: ";
string sPath;
getline(cin, sPath);
cout << "Please enter the password: ";
string sPassword; getline(cin, sPassword);

Problem is, when I run it it displays “Please enter the file path: ” then it displays “Please enter the password: ” and then waits for the password. It seems to completely skip the first ‘getline()’.

Later edit: Yes there are some input operations done before.

int iOption = 0;
while (iOption == 0)
{
    cout << "(E/D): ";
    switch (GetCH())
    {
    case 'E':
        iOption = 1;
        break;
    case 'e':
        iOption = 1;
        break;
    case 'D':
        iOption = 2;
        break;
    case 'd':
        iOption = 3;
        break;
    default:
        break;
    }
}

And the code for GetCH() in case anyone asks.

char GetCH ()
{
    char c;
    cin >> c;
    return c;
};

Answer 1

It looks like the rest of the line that was input for GetCH still remains in the buffer at the time that you call getline, i.e. at least a \n and this is what you are reading in the first getline call. The program doesn’t block waiting for user input because the getline request can be satisfied by the partial line still queued for reading.

Consider modifying your GetCH function to read whole lines as well.

E.g. something like (totally untested, I’m afraid):

int GetCH()
{
    std::string inputline;

    // Read until error or we receive a non-empty line
    while( std::getline(std::cin, inputline) && inputline.empty() )
    {
    }

    return inputline.empty() ? EOF : inputline[0];
}