Question

Here’s the function:

function getCount($module, $db_link) {
    if($module == "tweets") {
        $query = "SELECT COUNT(*) FROM tweets WHERE `read`='n'";
        $tweet_count = mysqli_query($db_link,$query);
        echo $tweet_count;
    }
}

Here’s the link (which is defined earlier in the code):

$mysqli = mysqli_connect("localhost", "twitterd", "password", "twitterd") or die('Cannot connect to the database');

The function call:

<?php getCount("tweets", $mysqli); ?>

How do I pass the $mysqli link to the getCount function? Currently, I get this error:

Catchable fatal error: Object of class mysqli_result could not be converted to string in lib.php on line 7

Answer 1

Everything is being passed just fine; the problem is this:

echo $tweet_count;

You can’t convert a MySQL resource to a string. Fetch the row:

$row = mysqli_fetch_row($tweet_count);
echo $row[0];