Question

Hi all i have a post value which i am checking to see if its been posted it has atleast 4 numbers (digits) this works perfect.

if (isset($_POST['year']) && 
      !preg_match('/([0-9]{4})/i', stripslashes(trim($_POST['year']))) ) {

now i want to check that the value is greater or = to a vairable and not sure how to achive what i need

i tried the below with no luck

$yearOff = date("Y")-150;
echo $yearOff;


    if (isset($_POST['year']) && 
            !preg_match('/([0-9]{4})/i', stripslashes(trim($_POST['year']))) 
            && $_POST['year'] > $yearOff ) {

                   $ageerrors[] = '<span class="error">
                                      You forgot enter your birth YEAR</span>';
    }

Answer 1

$yearOff = date("Y")-150;
echo $yearOff;

$input = @$_POST['year'];

if (!$input || strlen($input) !== 4 || $input < $yearoff) {
    ### MEEEP, ERROR ###
}

Explanation:

Input is set (not null which would be false), then it must have a string-length of four and finally it’s numerical value must be higher or equal $yearOff.

I assigned the value of the input to it’s own variable as well, because you only need to take it once out of $_POST.

As all these conditions are negated, I used the or || operator. Naturally the same can be expressed non-negated and with and:

if ($input && strlen($input) === 4 && $input >= $yearoff) {
    ### THIS IS CALL OKAY ###
}

To better debug this, the next step is to assign the validity to a variable as well:

$inputValid = $input && strlen($input) === 4 && $input >= $yearoff;
if (false === $inputValid) [
    ### MEEP, ERROR ####
}  

Hope this is helpful.