Question

Hi i have a simple code which prints three characters of a charater array as shown below

void main()
{
    char str[]={65,66,67};
    printf("%.3s",str);
}

this gives the output ABC,but i was wondering since this is not a string means it is not null terminated then how can %s work on it and give the correct result?

Answer 1

Since you passed the length of the string, no 0 terminator is required by printf.

7.21.6.1 – 8

If the precision is specified, no more than that many bytes are
written. If the precision is not specified or is greater than the size
of the array, the array shall contain a null character.