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Home/ Questions/Q 8230717
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T17:13:39+00:00 2026-06-07T17:13:39+00:00

Host: unsigned char exp[128]; unsigned char __e; i = cudaMalloc( (void**)&__e, 128 * sizeof(unsigned

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Host:

unsigned char exp[128];
unsigned char __e;

i = cudaMalloc( (void**)&__e, 128 * sizeof(unsigned char) );
if(i != cudaSuccess)
    printf("cudaMalloc __e FAIL! Code: %d\n", i);

BN_bn2bin128B(e, exp);  // copy data from e to exp, no problems since here

i = cudaMemcpy( &__e, &exp, 128 * sizeof(unsigned char), cudaMemcpyHostToDevice);
if(i != cudaSuccess)
    printf("cudaMemcpy __e FAIL! Code: %d\n", i);

Output:

cudaMemcpy __e FAIL! Code: 11

Error 11 corresponds to:

cudaErrorInvalidValue = 11, ///< Invalid value

Why? Where is the error?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T17:13:41+00:00Added an answer on June 7, 2026 at 5:13 pm

    You have declared __e incorrectly. It must be a pointer. Try this:

    unsigned char exp[128];
    unsigned char * __e;
    
    i = cudaMalloc( (void**)&__e, 128 * sizeof(unsigned char) );
    if(i != cudaSuccess)
        printf("cudaMalloc __e FAIL! Code: %d\n", i);
    
    // whatever goes here to set exp
    
    i = cudaMemcpy( __e, &exp[0], 128 * sizeof(unsigned char), cudaMemcpyHostToDevice);
    if(i != cudaSuccess)
        printf("cudaMemcpy __e FAIL! Code: %d\n", i);
    
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