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Home/ Questions/Q 8344573
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T06:24:47+00:00 2026-06-09T06:24:47+00:00

How can I avoid double logging in this situation? @AfterThrowing(pointcut=execution(String greeting(..)),throwing=e) public void itsAFoo1(JoinPoint

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How can I avoid double logging in this situation?

@AfterThrowing(pointcut="execution(String greeting(..))",throwing="e")
public void itsAFoo1(JoinPoint joinPoint, RemoteException e) {
    logger.error(joinPoint.getSignature().toLongString() + " exception here!");
}

@After("execution(String greeting(..))")
public void itsAFoo2(JoinPoint joinPoint, RemoteException e) {
    logger.error(joinPoint.getSignature().toLongString());
}

I got two logs:

[2012-08-07 17:02:01,585] [request1344351718430] [public java.lang.String componentC.Hello.greeting(java.lang.String) exception here!]
[2012-08-07 17:02:01,585] [request1344351718430] [public java.lang.String componentC.Hello.greeting(java.lang.String)]

But I need to receive one if there was an exception and one if there wasn’t.

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  1. Editorial Team
    Editorial Team
    2026-06-09T06:24:50+00:00Added an answer on June 9, 2026 at 6:24 am

    Change the @After to an @AfterReturning

    @AfterReturning("execution(String greeting(..))")
    public void itsAFoo2(JoinPoint joinPoint, RemoteException e) {
        logger.error(joinPoint.getSignature().toLongString());
    }
    
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