Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8317831
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T21:44:22+00:00 2026-06-08T21:44:22+00:00

How do I get the Cars and Features which have both Feature1 & Feature2

  • 0

How do I get the Cars and Features which have both Feature1 & Feature2 in below table (BMW and Toyota)?

Select Car,Feature 
    from Table 
    where Feature in ('Feature1','Feature2') 

gives all 3 cars, including Honda which has Feature1 only. This is just a simplified example of the actual query, which can have hundreds of values in the IN clause.

Car    Feature
-----  --------
BMW    Feature1
BMW    Feature2
BMW    Feature3
Toyota Feature1
Toyota Feature2
Honda  Feature1

Thanks,
Kiran

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-08T21:44:24+00:00Added an answer on June 8, 2026 at 9:44 pm
    select Car
    from your_table
    where feature in ('f1', 'f2')
    group by car
    having count(distinct feature) >= 2
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a class: public class CarList { public int quantity{get;set;} public List<Car> Cars
The reflection code below returns: System.Collections.Generic.IList`1[TestReflection.Car] Cars How can I get the Cars root
I have a car model. (In my database, the cars table has a column
I have a viewModel named CarsList with main property public ObservableCollection<Car> Cars { get
I have a table in LINQ to SQL called Cars that contains Car objects.
I have the following table as an example. id uid car 1 3 BMW
I have two classes: public class RichMan { public string ID {get;set;} List<Car> _cars=new
When I run the code below I get: Thank you for joining, ['cars', 'gas',
I have a Car class with various properties. I have a static Cars collection
I am dealing with a table that contains both cars and owners (table CO

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.