Question

How do you deal with lambdas in boo? Is ‘callable’ the same thing? How do you define a method that takes a lambda as a parameter?

Answer 1

Boo does support lambda expression syntax:

foo = {x|x+2} seven = foo(5) def TakeLambda(expr as callable(int) as int):    return expr(10) twelve = TakeLambda(foo) 

In this example, foo is a function that accepts a number x and returns x + 2. So calling foo(5) returns the number 7. TakeLambda is a function that accepts foo and evaluates it at 10.