Question

How do you pass an array to a function where that function can edit it’s contents?

like when doing

function(int *x)
 {*x = 10;}

main()
  {int x;
   function(&x);}

how could i do the same using a character array?

whenever I do

   function(char *array[], int *num)
   { int x = *num;
     *array[x] = 'A'; }

   main()
   { char this[5] = "00000"; //not a string
     int x = 3;
     function(&this, &x); }

DEV C++ says

[Warning] passing arg 1 of `function' from incompatible pointer type 

obviously I did something wrong, so please tell me how to fix that. Thanks 😀

Answer 1

You should write:

void function(char array[], int *num)
{
   int x = *num;
   array[x] = 'A';
}

void main()
{
   char my_array[5] = "00000";
   int x = 3;
   function(my_array, &x);
}

Notation char *array[] is an array of pointers that you do not need here.

When you pass an array somewhere, you should not take its address. Arrays are adjusted to pointers by default.

EDIT:

Function prototypes:

void function(char array[], int *num);
void function(char *array, int *num);

are absolutely identical. There is no even minor difference between them.