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How does the initialization happen in cases 2, 3, 4, 5 below. 1 will contain garbage.
char x[16];
char x[16] = {0};
char x[16] = {0, };
char x[16] = {1};
char x[16] = {1, };
If you use the brace initializer syntax with arrays, any additional elements not mentioned in the initializer list are initialized with zeros.